There are a variety of methods that can be used to Find the equation of a tangent line at a given point.

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So the Standard equation of tangent line: $$ y – y_1 = (m)(x – x_1)$$ Where (x_1 and y_1) are the line coordinate points and “m” is the slope of the line. Example: Find the tangent equation to the

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Finding Tangent Lines to a Curve at a Given Point Vocabulary and Formulas Derivative: The derivative is the instantaneous rate of change of the function at the given value of {eq}x=a

Find the equation of the tangent line to the given function at the specified point. f (x)= (x2 −6)4x3 at x= −2 The equation of the tangent line is y = Previous question Get more help from Chegg

Here are the steps to take to find the equation of a tangent line to a curve at a given point: Find the first derivative of f (x). Substitute x in f' (x) for the value of x 0 at the given point to find the

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tangent\:of\:f(x)=\frac{1}{x^2},\:(-1,\:1) tangent\:of\:f(x)=x^3+2x,\:\:x=0; tangent\:of\:f(x)=4x^2-4x+1,\:\:x=1; tangent\:of\:y=e^{-x}\cdot \ln(x),\:(1,0) tangent\:of\:f(x)=\sin (3x),\:(\frac{\pi