If we place the circle center at (0,0) and set the radius to 1 we get: (x−a) 2 + (y−b) 2 = r 2. (x−0) 2 + (y−0) 2 = 1 2. x2 + y2 = 1. Which is the equation of the Unit Circle.
Find the center and the radius of the circle $x^2 + y^2 + 2x - 3y - \frac{3}{4} = 0 $ example 3: ex 3: Find the equation of a circle in standard form, with a center at $C(-3,4)$ and passing through
[insert drawing of circle on graph with center point at (2, 3) and a radius r of 5] (x − a)2 + (y − b)2 = r2 x - a 2 + y - b 2 = r 2 (x − 2)2 + (y − 3)2 = 52 x - 2 2 + y - 3 2 = 5 2 Let's expand that so you can
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